The kittens get one gene from each parent for the drawing of the coat. These two genes together, so put the coat pattern together.
A homozygous contains the same two genes, that is to say with the same information, for example, spotted and spotted and marble or marble. A heterozygote contains two different kinds of genes, such as spotted and marble or marble and spotted.
Let's call the gene for spotted S. The gene for marble we call m. The gene for spotted is dominant, so we use a capital letter. This means that this gene is more powerful than a recessive gene and this will displace. The gene is recessive marble why we use lowercase.
The dominant gene is always expressed when present in its appearance. In conjunction with the dominant gene for spotted you do not see the marble recessive gene. The recessive gene is expressed ie only when no dominant gene is present. A marble coat you see so only if the cat does not carry gene for spotted.
When a cat looks on the outside spotted, he can still carry a recessive gene marble. Because the gene for spotted is dominant, you see no marble coat.
Or a look spotted cat wears a marble gene, you know for sure is if he or she has a marble parent, or if he or she has ever received marble posterity.
Suppose we have a homozygous spotted cat and a marble cat who just homozygous may be different she was not marble. The nest between these two parents will consist of:
- 100% heterozygous spotted; S father + mother of the m = Sm
- 50% heterozygous spotted; S + m from the father of the mother = Sm
- 50% homozygous marble; m + m from the father of the mother = mm
- 25% homozygous spotted; S + S of the father of the mother = SS
- 25% heterozygous spotted; S + m from the father of the mother = Sm
- 25% heterozygous spotted; m the father of the mother + S = mS
- 25% homozygous marble; m + m from the father of the mother = mm
This way you can work out all the possible combinations using the form below cal buddy.
Again, this is, in theory, possible combinations. Nature, however, can not be forced into schemes. So got my marble bengal Zahra proven heterozygous spotted hangover still only spotted kittens. The kittens were given m from Zahra who just meters can pass. The father gave this time only by the S to his kittens. M the father was not passed.
When was the next litter Zahra another proven hangover heterozygous spotted a nest with three marble kittens. The kittens were given m from Zahra who just meters can pass. This time the father only gave the m to his progeny. The S father was not passed.
Normally you would expect in these nests both times and marble spotted kittens.
Only if both parents are homozygous proven you can be sure that there is only one possible combination could be a nest.
SS x SS = SS
mm mm mm x =
SS mm x = Sm